[Libssh] channel_read - Save read characters in "string"

[Rico Kerster]

Thanks for the fast reply

Tried it with 
command_output.assign(buffer_get(readbuf),buffer_get_len(readbuf));

Though I get the following compiler error:
error: call of overloaded 'assign(void*, int)' is ambiguous|

I don't see how the first parameter can be a void*.

I really appreciate your effort and look forward to the new release.

Rico Kerster


> Date: Mon, 30 Jun 2008 00:19:33 +0200
> From: aris at 0xbadc0de.be
> To: libssh at cerkinfo.be
> Subject: Re: [Libssh] channel_read - Save read characters in "string"
>
> Rico Kerster a écrit :
>> Hello libssh-List
>> I successfully logged into my SSH server, can issue a command and output the comands' result to the terminal window (as in the example, I achieved that with the function "write()")
>>
>> string command_output;
>> char cmd[] = "date\n";
>> BUFFER *readbuf = buffer_new();
>> int num = channel_write(channel,cmd,sizeof(cmd));
>> num = channel_read(channel,readbuf,0,0);
>>
>> write(1,buffer_get(readbuf),buffer_get_len(readbuf));
>>
>> But now I'd like to store the content of readbuf in the string "command_output", I studied the _M_write() template and how "write()" gets out the characters but I couldn't manage to understand and copy it. So to sum up my question:
>>
>> How do I store the characters of readbuff (BUFFER) in command_output (string) or in a char[]?
>>
>> Thanks in Advance.
>>
> Hello,
>
> Consider the output of buffer_get like a char [] type string, except it
> is not nul terminated.
> http://www.cplusplus.com/reference/string/string/assign.html
> Look at string::assign(const char *s, size_t n);
>
> I's much like a C++ problem you've got. The next release of libssh will
> have a more classical channel_read() which won't require a BUFFER object.
>
> Regards,
> Aris
>
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